Question
$$3(x+1)^2-(x+3)^2 = 0$$
Answer
$$ \begin{matrix}x_1 = -\sqrt{ 3 } & x_2 = \sqrt{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3(x+1)^2-(x+3)^2 &= 0&& \text{simplify left side} \\[1 em]3(x^2+2x+1)-(x^2+6x+9) &= 0&& \\[1 em]3x^2+6x+3-(x^2+6x+9) &= 0&& \\[1 em]3x^2+6x+3-x^2-6x-9 &= 0&& \\[1 em]3x^2+6x+3-x^2-6x-9 &= 0&& \\[1 em]2x^2-6 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-6 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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