Question
$$3(x+1)(x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3(x+1)(x-3) &= 0&& \text{simplify left side} \\[1 em](3x+3)(x-3) &= 0&& \\[1 em]3x^2-9x+3x-9 &= 0&& \\[1 em]3x^2-6x-9 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-6x-9 = 0 $ is a quadratic equation.
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