$$ \begin{aligned} 3(5y+1) &= 18y&& \text{simplify left side} \\[1 em]15y+3 &= 18y&& \text{move the $ \color{blue}{ 18y } $ to the left side and $ \color{blue}{ 3 }$ to the right} \\[1 em]15y-18y &= -3&& \text{simplify left side} \\[1 em]-3y &= -3&& \text{ divide both sides by $ -3 $ } \\[1 em]y &= \frac{-3}{-3}&& \\[1 em]y &= 1&& \\[1 em] \end{aligned} $$

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