$$ \begin{aligned} 2y-5 &= 7y-5&& \text{move the $ \color{blue}{ 7y } $ to the left side and $ \color{blue}{ -5 }$ to the right} \\[1 em]2y-7y &= -5+5&& \text{simplify left and right hand side} \\[1 em]-5y &= 0&& \text{ divide both sides by $ -5 $ } \\[1 em]y &= \frac{0}{-5}&& \\[1 em]y &= 0&& \\[1 em] \end{aligned} $$
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