$$ \begin{aligned} 2y-3(y+4) &= 6y+23&& \text{simplify left side} \\[1 em]2y-(3y+12) &= 6y+23&& \\[1 em]2y-3y-12 &= 6y+23&& \\[1 em]-y-12 &= 6y+23&& \text{move the $ \color{blue}{ 6y } $ to the left side and $ \color{blue}{ -12 }$ to the right} \\[1 em]-y-6y &= 23+12&& \text{simplify left and right hand side} \\[1 em]-7y &= 35&& \text{ divide both sides by $ -7 $ } \\[1 em]y &= -\frac{35}{7}&& \\[1 em]y &= -5&& \\[1 em] \end{aligned} $$

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