Question
$$2x\cdot5+x\cdot4+x\cdot3-2x-3 = 0$$
Answer
$$ x = \dfrac{1}{5} $$
Explanation
$$ \begin{aligned} 2x\cdot5+x\cdot4+x\cdot3-2x-3 &= 0&& \text{simplify left side} \\[1 em]10x+4x+3x-2x-3 &= 0&& \\[1 em]15x-3 &= 0&& \text{ move the constants to the right } \\[1 em]15x &= 3&& \text{ divide both sides by $ 15 $ } \\[1 em]x &= \frac{3}{15}&& \\[1 em]x &= \frac{1}{5}&& \\[1 em] \end{aligned} $$
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