Question
$$2x\cdot2-32x+128 = 0$$
Answer
$$ x = \dfrac{32}{7} $$
Explanation
$$ \begin{aligned} 2x\cdot2-32x+128 &= 0&& \text{simplify left side} \\[1 em]4x-32x+128 &= 0&& \\[1 em]-28x+128 &= 0&& \text{ move the constants to the right } \\[1 em]-28x &= -128&& \text{ divide both sides by $ -28 $ } \\[1 em]x &= \frac{-128}{-28}&& \\[1 em]x &= \frac{32}{7}&& \\[1 em] \end{aligned} $$
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