$$ \begin{aligned} 2x-9-(x-3)(x+3)+(x-2)(2x-1) &= 0&& \text{simplify left side} \\[1 em]2x-9-(x^2+3x-3x-9)+2x^2-x-4x+2 &= 0&& \\[1 em]2x-9-(x^2-9)+2x^2-5x+2 &= 0&& \\[1 em]2x-9-x^2+9+2x^2-5x+2 &= 0&& \\[1 em]-x^2+2x+2x^2-5x+2 &= 0&& \\[1 em]x^2-3x+2 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-3x+2 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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