$$ \begin{aligned} 2 \cdot \frac{x^3}{x}+3-\frac{4}{x}-1 &= 0&& \text{multiply ALL terms by } \color{blue}{ x }. \\[1 em]x\cdot2 \cdot \frac{x^3}{x}+x\cdot3-x\cdot\frac{4}{x}-x\cdot1 &= x\cdot0&& \text{cancel out the denominators} \\[1 em]2x+3x-4-x &= 0&& \text{simplify left side} \\[1 em]4x-4 &= 0&& \text{ move the constants to the right } \\[1 em]4x &= 4&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= \frac{4}{4}&& \\[1 em]x &= 1&& \\[1 em] \end{aligned} $$

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