Question
$$2x^2-4x-8 = -x^2+x$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = \dfrac{ 8 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x^2-4x-8 &= -x^2+x&& \text{move all terms to the left hand side } \\[1 em]2x^2-4x-8+x^2-x &= 0&& \text{simplify left side} \\[1 em]3x^2-5x-8 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-5x-8 = 0 $ is a quadratic equation.
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