Question
$$2v^2+4v+3 = 5$$
Answer
$$ \begin{matrix}v_1 = -1-\sqrt{ 2 } & v_2 = -1+\sqrt{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2v^2+4v+3 &= 5&& \text{move all terms to the left hand side } \\[1 em]2v^2+4v+3-5 &= 0&& \text{simplify left side} \\[1 em]2v^2+4v-2 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}+4x-2 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver