$$ \begin{aligned} 2 \cdot \frac{n}{3}-4 &= \frac{1}{4}+n&& \text{multiply ALL terms by } \color{blue}{ 12 }. \\[1 em]12\cdot2 \cdot \frac{n}{3}-12\cdot4 &= 12\cdot\frac{1}{4}+12n&& \text{cancel out the denominators} \\[1 em]8n-48 &= 3+12n&& \text{move the $ \color{blue}{ 12n } $ to the left side and $ \color{blue}{ -48 }$ to the right} \\[1 em]8n-12n &= 3+48&& \text{simplify left and right hand side} \\[1 em]-4n &= 51&& \text{ divide both sides by $ -4 $ } \\[1 em]n &= -\frac{51}{4}&& \\[1 em] \end{aligned} $$

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