$$ \begin{aligned} 27-3(4x-(x\cdot2+5-x\cdot3))+17x\cdot2 &= 0&& \text{simplify left side} \\[1 em]27-3(4x-(-x+5))+34x &= 0&& \\[1 em]27-3(4x+x-5)+34x &= 0&& \\[1 em]27-3(5x-5)+34x &= 0&& \\[1 em]27-(15x-15)+34x &= 0&& \\[1 em]27-15x+15+34x &= 0&& \\[1 em]19x+42 &= 0&& \text{ move the constants to the right } \\[1 em]19x &= -42&& \text{ divide both sides by $ 19 $ } \\[1 em]x &= -\frac{42}{19}&& \\[1 em] \end{aligned} $$

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