Question
$$25(2\cdot(8-3)-8) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 25(2\cdot(8-3)-8) &= 0&& \text{simplify left side} \\[1 em]25(2\cdot5-8) &= 0&& \\[1 em]25\cdot(10-8) &= 0&& \\[1 em]25\cdot2 &= 0&& \\[1 em]50 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 50 = 0 } $ is FALSE, we conclude that the equation has no solution.
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