Question
$$24-(5+3)^2+4\cdot2 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 24-(5+3)^2+4\cdot2 &= 0&& \text{simplify left side} \\[1 em]24-8^2+8 &= 0&& \\[1 em]24-64+8 &= 0&& \\[1 em]-32 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ -32 = 0 } $ is FALSE, we conclude that the equation has no solution.
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