Question
$$22 = 8x-2x\cdot(1+x)$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 35 }}{ 2 }i & x_2 = \dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 35 }}{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 22 &= 8x-2x\cdot(1+x)&& \text{simplify right side} \\[1 em]22 &= 8x-(2x+2x^2)&& \\[1 em]22 &= 8x-2x-2x^2&& \\[1 em]22 &= -2x^2+6x&& \text{move all terms to the left hand side } \\[1 em]22+2x^2-6x &= 0&& \text{simplify left side} \\[1 em]2x^2-6x+22 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-6x+22 = 0 $ is a quadratic equation.
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