$$ \begin{aligned} 2x\cdot(5-4)+6x \cdot \frac{7-3}{2} &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]22x\cdot(5-4)+26x \cdot \frac{7-3}{2} &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]4x+24x &= 0&& \text{simplify left side} \\[1 em]28x &= 0&& \text{ divide both sides by $ 28 $ } \\[1 em]x &= \frac{0}{28}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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