$$ \begin{aligned} 2(x-(4+2x)+3)-2x-2 &= 4(2x-(3-x)+5)+6x+28&& \text{simplify left and right hand side} \\[1 em]2(x-4-2x+3)-2x-2 &= 4(2x-3+x+5)+6x+28&& \\[1 em]2(-x-1)-2x-2 &= 4(3x+2)+6x+28&& \\[1 em]-2x-2-2x-2 &= 12x+8+6x+28&& \\[1 em]-4x-4 &= 18x+36&& \text{move the $ \color{blue}{ 18x } $ to the left side and $ \color{blue}{ -4 }$ to the right} \\[1 em]-4x-18x &= 36+4&& \text{simplify left and right hand side} \\[1 em]-22x &= 40&& \text{ divide both sides by $ -22 $ } \\[1 em]x &= -\frac{40}{22}&& \\[1 em]x &= -\frac{20}{11}&& \\[1 em] \end{aligned} $$

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