$$ \begin{aligned} 2 &= \frac{3}{5}h+3&& \text{multiply ALL terms by } \color{blue}{ 5 }. \\[1 em]5\cdot2 &= 5 \cdot \frac{3}{5}h+5\cdot3&& \text{cancel out the denominators} \\[1 em]10 &= 3h+15&& \text{ swap the left and right side of the equation } \\[1 em]3h+15 &= 10&& \text{ move 15 to the right } \\[1 em]3h &= 10-15&& \\[1 em]3h &= -5&& \text{ divide both sides by $ 3 $ } \\[1 em]h &= -\frac{5}{3}&& \\[1 em] \end{aligned} $$

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