Question
$$2^2-(3x+10) = 0$$
Answer
$$ x = -2 $$
Explanation
$$ \begin{aligned} 2^2-(3x+10) &= 0&& \text{simplify left side} \\[1 em]4-(3x+10) &= 0&& \\[1 em]4-3x-10 &= 0&& \\[1 em]-3x-6 &= 0&& \text{ move the constants to the right } \\[1 em]-3x &= 6&& \text{ divide both sides by $ -3 $ } \\[1 em]x &= -\frac{6}{3}&& \\[1 em]x &= -2&& \\[1 em] \end{aligned} $$
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