$$ \begin{aligned} \frac{2}{5}x+7 &= \frac{6}{5}x+3&& \text{multiply ALL terms by } \color{blue}{ 5 }. \\[1 em]5 \cdot \frac{2}{5}x+5\cdot7 &= 5 \cdot \frac{6}{5}x+5\cdot3&& \text{cancel out the denominators} \\[1 em]2x+35 &= 6x+15&& \text{move the $ \color{blue}{ 6x } $ to the left side and $ \color{blue}{ 35 }$ to the right} \\[1 em]2x-6x &= 15-35&& \text{simplify left and right hand side} \\[1 em]-4x &= -20&& \text{ divide both sides by $ -4 $ } \\[1 em]x &= \frac{-20}{-4}&& \\[1 em]x &= 5&& \\[1 em] \end{aligned} $$

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