$$ \begin{aligned} \frac{2}{3}\cdot(12-9)-3x+5 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3 \cdot \frac{2}{3}\cdot(12-9)-3\cdot3x+3\cdot5 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]6-9x+15 &= 0&& \text{simplify left side} \\[1 em]-9x+21 &= 0&& \text{ move the constants to the right } \\[1 em]-9x &= -21&& \text{ divide both sides by $ -9 $ } \\[1 em]x &= \frac{-21}{-9}&& \\[1 em]x &= \frac{7}{3}&& \\[1 em] \end{aligned} $$

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