Question
$$2(x+4)\cdot3(x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2(x+4)\cdot3(x-1) &= 0&& \text{simplify left side} \\[1 em](2x+8)\cdot3(x-1) &= 0&& \\[1 em](6x+24)(x-1) &= 0&& \\[1 em]6x^2-6x+24x-24 &= 0&& \\[1 em]6x^2+18x-24 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}+18x-24 = 0 $ is a quadratic equation.
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