$$ \begin{aligned} 2(x-5)\cdot2+2(x-5)+4 &= 0&& \text{simplify left side} \\[1 em](2x-10)\cdot2+2x-10+4 &= 0&& \\[1 em]4x-20+2x-10+4 &= 0&& \\[1 em]6x-30+4 &= 0&& \\[1 em]6x-26 &= 0&& \text{ move the constants to the right } \\[1 em]6x &= 26&& \text{ divide both sides by $ 6 $ } \\[1 em]x &= \frac{26}{6}&& \\[1 em]x &= \frac{13}{3}&& \\[1 em] \end{aligned} $$

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