$$ \begin{aligned} 2(x-4)+3x &= x+12&& \text{simplify left side} \\[1 em]2x-8+3x &= x+12&& \\[1 em]5x-8 &= x+12&& \text{move the $ \color{blue}{ x } $ to the left side and $ \color{blue}{ -8 }$ to the right} \\[1 em]5x-x &= 12+8&& \text{simplify left and right hand side} \\[1 em]4x &= 20&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= \frac{20}{4}&& \\[1 em]x &= 5&& \\[1 em] \end{aligned} $$

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