Question
$$2(x-4)\cdot2+5(x-4)-4 = 0$$
Answer
$$ x = \dfrac{40}{9} $$
Explanation
$$ \begin{aligned} 2(x-4)\cdot2+5(x-4)-4 &= 0&& \text{simplify left side} \\[1 em](2x-8)\cdot2+5x-20-4 &= 0&& \\[1 em]4x-16+5x-20-4 &= 0&& \\[1 em]9x-36-4 &= 0&& \\[1 em]9x-40 &= 0&& \text{ move the constants to the right } \\[1 em]9x &= 40&& \text{ divide both sides by $ 9 $ } \\[1 em]x &= \frac{40}{9}&& \\[1 em] \end{aligned} $$
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