Question
$$2(4x+4)^2+2(4x+4) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -\dfrac{ 5 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2(4x+4)^2+2(4x+4) &= 0&& \text{simplify left side} \\[1 em]2(16x^2+32x+16)+2(4x+4) &= 0&& \\[1 em]32x^2+64x+32+8x+8 &= 0&& \\[1 em]32x^2+72x+40 &= 0&& \\[1 em] \end{aligned} $$
$ 32x^{2}+72x+40 = 0 $ is a quadratic equation.
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