$$ \begin{aligned} 2\cdot(4-\frac{1}{3}u) &= -u+2&& \text{simplify left side} \\[1 em]2\cdot(4-\frac{u}{3}) &= -u+2&& \\[1 em]2 \cdot \frac{-u+12}{3} &= -u+2&& \\[1 em]\frac{-2u+24}{3} &= -u+2&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3 \cdot \frac{-2u+24}{3} &= -3u+3\cdot2&& \text{cancel out the denominators} \\[1 em]-2u+24 &= -3u+6&& \text{move the $ \color{blue}{ -3u } $ to the left side and $ \color{blue}{ 24 }$ to the right} \\[1 em]-2u+3u &= 6-24&& \text{simplify left and right hand side} \\[1 em]u &= -18&& \\[1 em]u &= -18&& \\[1 em] \end{aligned} $$

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