$$ \begin{aligned} 2(3x\cdot2+2x\cdot3-9-4x\cdot2-5x+1-3x\cdot3+x\cdot2) &= 0&& \text{simplify left side} \\[1 em]2(6x+6x-9-8x-5x+1-9x+2x) &= 0&& \\[1 em]2(-8x-8) &= 0&& \\[1 em]-16x-16 &= 0&& \text{ move the constants to the right } \\[1 em]-16x &= 16&& \text{ divide both sides by $ -16 $ } \\[1 em]x &= -\frac{16}{16}&& \\[1 em]x &= -1&& \\[1 em] \end{aligned} $$

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