Question
$$\frac{18}{3x\cdot3}+4 = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -\dfrac{ 2 }{ 9 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{18}{3x\cdot3}+4 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3x }. \\[1 em]3x\cdot\frac{18}{3x\cdot3}+3x\cdot4 &= 3x\cdot0&& \text{cancel out the denominators} \\[1 em]54x^2+12x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 54x^{2}+12x = 0 } $, first we need to factor our $ x $.
$$ 54x^{2}+12x = x \left( 54x+12 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 54x+12 = 0$.
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