Question
$$16 = 4(x-6)^2$$
Answer
$$ \begin{matrix}x_1 = 4 & x_2 = 8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 16 &= 4(x-6)^2&& \text{simplify right side} \\[1 em]16 &= 4(x^2-12x+36)&& \\[1 em]16 &= 4x^2-48x+144&& \text{move all terms to the left hand side } \\[1 em]16-4x^2+48x-144 &= 0&& \text{simplify left side} \\[1 em]-4x^2+48x-128 &= 0&& \\[1 em] \end{aligned} $$
$ -4x^{2}+48x-128 = 0 $ is a quadratic equation.
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