$$ \begin{aligned} 15x-15 &= 3x+33&& \text{move the $ \color{blue}{ 3x } $ to the left side and $ \color{blue}{ -15 }$ to the right} \\[1 em]15x-3x &= 33+15&& \text{simplify left and right hand side} \\[1 em]12x &= 48&& \text{ divide both sides by $ 12 $ } \\[1 em]x &= \frac{48}{12}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$
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