Question
$$15+(3+2)^2-9x\cdot6+2^3 = 0$$
Answer
$$ x = \dfrac{8}{9} $$
Explanation
$$ \begin{aligned} 15+(3+2)^2-9x\cdot6+2^3 &= 0&& \text{simplify left side} \\[1 em]15+5^2-54x+2^3 &= 0&& \\[1 em]15+25-54x+8 &= 0&& \\[1 em]-54x+48 &= 0&& \text{ move the constants to the right } \\[1 em]-54x &= -48&& \text{ divide both sides by $ -54 $ } \\[1 em]x &= \frac{-48}{-54}&& \\[1 em]x &= \frac{8}{9}&& \\[1 em] \end{aligned} $$
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