$$ \begin{aligned} 15 &= 3(z-11)&& \text{simplify right side} \\[1 em]15 &= 3z-33&& \text{ swap the left and right side of the equation } \\[1 em]3z-33 &= 15&& \text{ move -33 to the right } \\[1 em]3z &= 15+33&& \\[1 em]3z &= 48&& \text{ divide both sides by $ 3 $ } \\[1 em]z &= \frac{48}{3}&& \\[1 em]z &= 16&& \\[1 em] \end{aligned} $$
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