$$ \begin{aligned} \frac{15}{3}+6x\cdot2-4 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot\frac{15}{3}+36x\cdot2-3\cdot4 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]15+36x-12 &= 0&& \text{simplify left side} \\[1 em]36x+3 &= 0&& \text{ move the constants to the right } \\[1 em]36x &= -3&& \text{ divide both sides by $ 36 $ } \\[1 em]x &= -\frac{3}{36}&& \\[1 em]x &= -\frac{1}{12}&& \\[1 em] \end{aligned} $$

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