Question
$$14(b-1)+4 = 2(7b-5)$$
Answer
The equation has an infinite number of solutions.
Explanation
$$ \begin{aligned} 14(b-1)+4 &= 2(7b-5)&& \text{simplify left and right hand side} \\[1 em]14b-14+4 &= 14b-10&& \\[1 em]14b-10 &= 14b-10&& \text{move the $ \color{blue}{ 14b } $ to the left side and $ \color{blue}{ -10 }$ to the right} \\[1 em]14b-14b &= -10+10&& \text{simplify left and right hand side} \\[1 em]14b-14b &= 0&& \\[1 em]0 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 0 = 0 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
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