Question
$$13-3\cdot2+4\cdot(-3)+1-(-10-(-6)) = 0$$
Answer
The equation has an infinite number of solutions.
Explanation
$$ \begin{aligned} 13-3\cdot2+4\cdot(-3)+1-(-10-(-6)) &= 0&& \text{simplify left side} \\[1 em]13-6-12+1-(-4) &= 0&& \\[1 em]13-6-12+1-(-4) &= 0&& \\[1 em]0 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 0 = 0 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
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