$$ \begin{aligned} 12-\frac{6}{3}x\cdot2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot12-3 \cdot \frac{6}{3}x\cdot2 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]36-12x &= 0&& \text{ move the constants to the right } \\[1 em]-12x &= -36&& \text{ divide both sides by $ -12 $ } \\[1 em]x &= \frac{-36}{-12}&& \\[1 em]x &= 3&& \\[1 em] \end{aligned} $$

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