$$ \begin{aligned} 12(x+10)-4\cdot(9+x) &= 0&& \text{simplify left side} \\[1 em]12x+120-(36+4x) &= 0&& \\[1 em]12x+120-36-4x &= 0&& \\[1 em]8x+84 &= 0&& \text{ move the constants to the right } \\[1 em]8x &= -84&& \text{ divide both sides by $ 8 $ } \\[1 em]x &= -\frac{84}{8}&& \\[1 em]x &= -\frac{21}{2}&& \\[1 em] \end{aligned} $$
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