Question
$$10x(10x\cdot6+2^2)+2 = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 30 }+\dfrac{\sqrt{ 2 }}{ 30 }i & x_2 = -\dfrac{ 1 }{ 30 }-\dfrac{\sqrt{ 2 }}{ 30 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 10x(10x\cdot6+2^2)+2 &= 0&& \text{simplify left side} \\[1 em]10x(60x+2^2)+2 &= 0&& \\[1 em]10x(60x+4)+2 &= 0&& \\[1 em]600x^2+40x+2 &= 0&& \\[1 em] \end{aligned} $$
$ 600x^{2}+40x+2 = 0 $ is a quadratic equation.
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