$$ \begin{aligned} 10(x+3) &= 5(3x+6)&& \text{simplify left and right hand side} \\[1 em]10x+30 &= 15x+30&& \text{move the $ \color{blue}{ 15x } $ to the left side and $ \color{blue}{ 30 }$ to the right} \\[1 em]10x-15x &= 30-30&& \text{simplify left and right hand side} \\[1 em]-5x &= 0&& \text{ divide both sides by $ -5 $ } \\[1 em]x &= \frac{0}{-5}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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