Question
$$1-(x-3)^2 = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 1-(x-3)^2 &= 0&& \text{simplify left side} \\[1 em]1-(x^2-6x+9) &= 0&& \\[1 em]1-x^2+6x-9 &= 0&& \\[1 em]-x^2+6x-8 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+6x-8 = 0 $ is a quadratic equation.
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