$$ \begin{aligned} \frac{1}{4}y+11 &= \frac{1}{5}y&& \text{multiply ALL terms by } \color{blue}{ 20 }. \\[1 em]20 \cdot \frac{1}{4}y+20\cdot11 &= 20 \cdot \frac{1}{5}y&& \text{cancel out the denominators} \\[1 em]5y+220 &= 4y&& \text{move the $ \color{blue}{ 4y } $ to the left side and $ \color{blue}{ 220 }$ to the right} \\[1 em]5y-4y &= -220&& \text{simplify left side} \\[1 em]y &= -220&& \\[1 em]y &= -220&& \\[1 em] \end{aligned} $$

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