$$ \begin{aligned} \frac{1}{4}(n+3) &= 2-n&& \text{simplify left and right hand side} \\[1 em]\frac{n+3}{4} &= -n+2&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{n+3}{4} &= 4\cdot-n+4\cdot2&& \text{cancel out the denominators} \\[1 em]n+3 &= -4n+8&& \text{move the $ \color{blue}{ -4n } $ to the left side and $ \color{blue}{ 3 }$ to the right} \\[1 em]n+4n &= 8-3&& \text{simplify left and right hand side} \\[1 em]5n &= 5&& \text{ divide both sides by $ 5 $ } \\[1 em]n &= \frac{5}{5}&& \\[1 em]n &= 1&& \\[1 em] \end{aligned} $$

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