$$ \begin{aligned} \frac{1}{3}-2x &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot\frac{1}{3}-3\cdot2x &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]1-6x &= 0&& \text{ move the constants to the right } \\[1 em]-6x &= -1&& \text{ divide both sides by $ -6 $ } \\[1 em]x &= \frac{-1}{-6}&& \\[1 em]x &= \frac{1}{6}&& \\[1 em] \end{aligned} $$

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