$$ \begin{aligned} \frac{1}{2}x+3 &= \frac{1}{5}-2x&& \text{multiply ALL terms by } \color{blue}{ 10 }. \\[1 em]10 \cdot \frac{1}{2}x+10\cdot3 &= 10\cdot\frac{1}{5}-10\cdot2x&& \text{cancel out the denominators} \\[1 em]5x+30 &= 2-20x&& \text{move the $ \color{blue}{ -20x } $ to the left side and $ \color{blue}{ 30 }$ to the right} \\[1 em]5x+20x &= 2-30&& \text{simplify left and right hand side} \\[1 em]25x &= -28&& \text{ divide both sides by $ 25 $ } \\[1 em]x &= -\frac{28}{25}&& \\[1 em] \end{aligned} $$
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