$$ \begin{aligned} 0 &= (x+2)^3-x^2(x+6)&& \text{simplify right side} \\[1 em]0 &= x^3+6x^2+12x+8-x^2(x+6)&& \\[1 em]0 &= x^3+6x^2+12x+8-(x^3+6x^2)&& \\[1 em]0 &= x^3+6x^2+12x+8-x^3-6x^2&& \\[1 em]0 &= x^3+6x^2+12x+8-x^3-6x^2&& \\[1 em]0 &= 12x+8&& \text{ swap the left and right side of the equation } \\[1 em]12x+8 &= 0&& \text{ move the constants to the right } \\[1 em]12x &= -8&& \text{ divide both sides by $ 12 $ } \\[1 em]x &= -\frac{8}{12}&& \\[1 em]x &= -\frac{2}{3}&& \\[1 em] \end{aligned} $$

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