Question
$$-z^2 = -38$$
Answer
$$ \begin{matrix}z_1 = -\sqrt{ 38 } & z_2 = \sqrt{ 38 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -z^2 &= -38&& \text{move all terms to the left hand side } \\[1 em]-z^2+38 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+38 = 0 $ is a quadratic equation.
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