Question
$$-7x+3(x-(3-2x)) = 0$$
Answer
$$ x = \dfrac{9}{2} $$
Explanation
$$ \begin{aligned} -7x+3(x-(3-2x)) &= 0&& \text{simplify left side} \\[1 em]-7x+3(x-3+2x) &= 0&& \\[1 em]-7x+3(3x-3) &= 0&& \\[1 em]-7x+9x-9 &= 0&& \\[1 em]2x-9 &= 0&& \text{ move the constants to the right } \\[1 em]2x &= 9&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= \frac{9}{2}&& \\[1 em] \end{aligned} $$
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