Question
$$-5(x+3)^2-6 = 0$$
Answer
$$ \begin{matrix}x_1 = -3+\dfrac{\sqrt{ 30 }}{ 5 }i & x_2 = -3-\dfrac{\sqrt{ 30 }}{ 5 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -5(x+3)^2-6 &= 0&& \text{simplify left side} \\[1 em]-5(x^2+6x+9)-6 &= 0&& \\[1 em]-(5x^2+30x+45)-6 &= 0&& \\[1 em]-5x^2-30x-45-6 &= 0&& \\[1 em]-5x^2-30x-51 &= 0&& \\[1 em] \end{aligned} $$
$ -5x^{2}-30x-51 = 0 $ is a quadratic equation.
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